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Start sum = 0; for(a = 42; a <= 44; a ++) { b = a % 10 d = (a - b) / 10 { for(c = 40; c <= 49; c ++) e = c % 10 if((b + e) == 10) { f = ((d + 1) * d * 100 + (b * e)) sum = sum + f } } } count = 0 while(sum >= 100) { count ++ sum = sum – 100 } Output count End
2 comments:
Start
sum = 0;
for(a = 42; a <= 44; a ++)
{ b = a % 10
d = (a - b) / 10
{ for(c = 40; c <= 49; c ++)
e = c % 10
if((b + e) == 10)
{ f = ((d + 1) * d * 100 + (b * e))
sum = sum + f
}
}
}
count = 0
while(sum >= 100)
{
count ++
sum = sum – 100
} Output count
End
write a program that is likely to display the following o/p
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