2. Write a c program to convert decimal number to octal number.
3. Write a c program to convert decimal number to hexadecimal number.
4. Write a c program to convert octal number to binary number.
3. Write a c program to convert decimal number to hexadecimal number.
4. Write a c program to convert octal number to binary number.
6. Write a c program to convert octal number to hexadecimal number.
8. Write a c program to convert hexadecimal number to octal number.
9. Write a c program to convert hexadecimal number to decimal number.
10. Write a c program to convert binary number to octal number.
9. Write a c program to convert hexadecimal number to decimal number.
10. Write a c program to convert binary number to octal number.
12. Write a c program to convert binary number to hexadecimal number.
13. C program for addition of binary numbers .
14. C program for multiplication of two binary numbers.
15. C program fractional binary conversion from decimal.
16. C program for fractional decimal to binary fraction conversion.
17. C program to convert decimal number to roman.
18. C program to convert roman number to decimal number.
19. C program to convert each digits of a number in words
20. C program to convert currency or number in word.
13. C program for addition of binary numbers .
14. C program for multiplication of two binary numbers.
15. C program fractional binary conversion from decimal.
16. C program for fractional decimal to binary fraction conversion.
17. C program to convert decimal number to roman.
18. C program to convert roman number to decimal number.
19. C program to convert each digits of a number in words
20. C program to convert currency or number in word.
14 comments:
i want examples of programs using bitwise operators..(like left shift,right shift etc)
while(binary1!=0||binary2!=0)
this can be efficiently written as
while(binary1||binary2)
Also what happens if the numbers are negative ?
Where is the validation for the given number is binary or not.
please help me with c or c++ program that can do addition of two number in octel notation,that is base8.
there is my code:
#include
#include
int main(){
long int octel1,octel2;
int i=0,remainder = 0,sum[20];
printf("Enter any first octel number: ");
scanf("%ld",&octel1);
printf("Enter any second octel number: ");
scanf("%ld",&octel2);
while(octel1!=0||octel2!=0){
sum[i++] = (octel1 %10 + octel2 %10 + remainder ) %8;
remainder = (octel1 %10 + octel2 %10 + remainder ) / 8;
octel1 = octel1/10;
octel2 = octel2/10;
}
if(remainder!=0)
sum[i++] = remainder;
--i;
printf("Sum of two octel numbers: ");
while(i>=0)
printf("%d",sum[i--]);
system("pause");
return 0;
}
it is very urgent. thanks in advance
you have to delete one #include, then make the other #include an #include stdio.h, and (sorry for my bad english) less than and greater than symbols must be put before and after the stdio.h word, I don't know why but i can't use them here.
void adder(int a,int b,int ci){
int na,nb,s;
if ((a==0) && (b==0)){printf("%d ",ci); return;}
na=a%10;
nb=b%10;
if((na==1)&& (nb==1) && (ci==1)){
s=1; ci=1;}
if (((na==0)&&(nb==0)&&(ci==1))||
((na==0)&&(nb==1)&&(ci==0))||
((na==1)&&(nb==0)&&(ci==0))){
s=1;
ci=0;}
if (((na==0)&&(nb==1)&&(ci==1))||
((na==1)&&(nb==0)&&(ci==1))||
((na==1)&&(nb==1)&&(ci==0)))
{s=0; ci=1;}
adder(a/10,b/10,ci);
printf("%d ",s);
}
Rule of binary addition:
1 + 1 = 0 (not 1 as u mentioned) and carry = 1
can I do it without using array /
?
can you reply c code for subtraction of 2 unsigned integer binary number.... thnx in adv :D
why the --i ???
Can u please help me how to write a program to find the carry, sum, and checksum of 4 16-bit binary numbers. The input and
output will be in binary format. Please do error checking for non-binary number.
try to add 1, and 10 ... ;) it will not work
It can be solved without using array with the help of recursion.
Also the above code won't work if both the inputs are '0'
For ex: '000000' , '0000'
#include
void add(long int bin1,long int bin2,int remainder)
{
int sum;
if(bin1==0&&bin2==0)
{
printf("%d ",bin1);
return;
}
sum=(bin1%10 +bin2%10 +remainder)%2;
remainder=(bin1%10 +bin2%10 +remainder)/2;
bin1/=10;
bin2/=10;
add(bin1,bin2,remainder);
if(remainder!=0&&bin1==0&&bin2==0)
printf("%d ",remainder);
printf("%d ",sum);
}
int main()
{
long int bin1,bin2;
int i=0,j=0;
scanf("%ld %ld",&bin1,&bin2);
add(bin1,bin2,0);
return 0;
}
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