C program for multiplication of two binary numbers

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C code for product of two binary numbers

C program for multiplication of two binary numbers

#include<stdio.h>

int binaryAddition(int,int);

int main(){

    long int binary1,binary2,multiply=0;

    int digit,factor=1;

    printf("Enter any first binary number: ");

    scanf("%ld",&binary1);

    printf("Enter any second binary number: ");

    scanf("%ld",&binary2);

    while(binary2!=0){

         digit =  binary2 %10;

         if(digit ==1){

                 binary1=binary1*factor;

                 multiply = binaryAddition(binary1,multiply);

         }

         else

             binary1=binary1*factor;

   

         binary2 = binary2/10;

         factor = 10;

    }

    printf("Product of two binary numbers: %ld",multiply);

   

   return 0;

}

int binaryAddition(int binary1,int binary2){

    int i=0,remainder = 0,sum[20];

    int binarySum=0;

    while(binary1!=0||binary2!=0){

         sum[i++] =  (binary1 %10 + binary2 %10 + remainder ) % 2;

         remainder = (binary1 %10 + binary2 %10 + remainder ) / 2;

         binary1 = binary1/10;

         binary2 = binary2/10;

    }

    if(remainder!=0)

         sum[i++] = remainder;

    --i;

    while(i>=0)

         binarySum = binarySum*10 + sum[i--];

    return binarySum;

}

Sample output:

Enter any first binary number: 1101

Enter any second binary number: 11

Product of two binary numbers: 100111

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Algorithm:

Rule of binary multiplication:

0 * 0 = 0

1 * 0 = 0

0 * 1 = 0

1 * 1 = 1

Q. what is the product of the binary numbers 0110 and 0011?

Answer: 0110 * 0011 = 10010

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