C program to convert decimal to roman number



Convert numbers to roman numerals in c

#include<stdio.h>

void predigits(char c1,char c2);
void postdigits(char c,int n);

char roman_Number[1000];
int i=0;

int main(){

    int j;
    long int number;
   
    printf("Enter any natural number: ");
    scanf("%d",&number);
   
    if(number <= 0){
         printf("Invalid number");
         return 0;
    }

    while(number != 0){

         if(number >= 1000){
             postdigits('M',number/1000);
             number = number - (number/1000) * 1000;
         }
         else if(number >=500){
             if(number < (500 + 4 * 100)){
                 postdigits('D',number/500);
                 number = number - (number/500) * 500;
             }
             else{
                 predigits('C','M');
                 number = number - (1000-100);
             }
         }
         else if(number >=100){
             if(number < (100 + 3 * 100)){
                 postdigits('C',number/100);
                 number = number - (number/100) * 100;
             }
             else{
                 predigits('L','D');
                 number = number - (500-100);
             }
         }
         else if(number >=50){
             if(number < (50 + 4 * 10)){
                 postdigits('L',number/50);
                 number = number - (number/50) * 50;
             }
             else{
                 predigits('X','C');
                 number = number - (100-10);
             }
         }
         else if(number >=10){
             if(number < (10 + 3 * 10)){
                 postdigits('X',number/10);
                 number = number - (number/10) * 10;
             }
             else{
                 predigits('X','L');
                 number = number - (50-10);
             }
         }
         else if(number >=5){
             if(number < (5 + 4 * 1)){
                 postdigits('V',number/5);
                 number = number - (number/5) * 5;
             }
             else{
                 predigits('I','X');
                 number = number - (10-1);
             }
         }
         else if(number >=1){
             if(number < 4){
                 postdigits('I',number/1);
                 number = number - (number/1) * 1;
             }
             else{
                 predigits('I','V');
                 number = number - (5-1);
             }
         }
    }

    printf("Roman number will be: ");
    for(j=0;j<i;j++)
         printf("%c",roman_Number[j]);

    return 0;

}

void predigits(char c1,char c2){
    roman_Number[i++] = c1;
    roman_Number[i++] = c2;
}

void postdigits(char c,int n){
    int j;
    for(j=0;j<n;j++)
         roman_Number[i++] = c;
   
}

Sample output:

Enter any natural number: 87
Roman number will be: LXXXVII



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10 comments:

Lostpoet said...

much better program with not so many conditionals.


---------------------------------------------------
#include
#include
#include
void reverse(char a[]);
void roman(int x,char a[],int i);
char values[4][3] = {{'I','V','X'},{'X','L','C'},{'C','D','M'},{'C'}};
main()
{
clrscr();
char final[20] = {'\0'};
int num,x,i=0;
printf("Enter the number that you want to convert to Roman Numerals:");
scanf("%d",&num);
if (num>5399)
num=0;
while(num)
{
x = num%10;
num /=10;
roman(x,final,i);
i++;
}
reverse(final);
printf("%s",&final);
getch();
return 1;
}
void roman(int x, char final[],int i)
{
int j=0,k=0,flag=0;
while (final[j]!='\0')
j++;
if(x<4)
{
for (k=0;k4)&&(x<9))
{
k=x-5;
final[j++]=values[i][1];
while (k)
{
final[j++]=values[i][0];
k--;
}
flag=1;
}
else if (x==9)
{
final[j++]=values[i][0];
final[j++]=values[i+1][0];
flag=1;
}
if(flag)
final[j++]='\0';
}
void reverse(char string[])
{
int j=0,k=0;
char temp[50];
while(string[j])
j++;
while(j)
temp[--j]=string[k++];
temp[k]='\0';
strcpy(string,temp);
}




------------------------------------------------

4/4/13, 2:51 AM
Lostpoet said...

the formatting of the website removed all the indentation.

4/4/13, 2:52 AM
Unknown said...

void dec2romanstr(int num){
int del[] = {1000,900,500,400,100,90,50,40,10,9,5,4,1};
char * sym[] = { "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" };
char res[64] = "\0";
int i = 0;
while (num){
while (num/del[i]){
strcat(res, sym[i]);
num -= del[i];
}
i++;
}
puts(res);
}

11/4/14, 2:40 AM
Unknown said...

Sir this program is not working for the number: 495.....i dont know why this error s occuring and i m unable to debug ur program as well so i kindly request you to provide a correct program ........

1/6/15, 11:51 AM
kanishk said...

#include

int main ()
{int year,q,w,e,r,t,y,u,i,o;
printf("enter ur num");
scanf("%d",&year);
q=year/1000;
w=year%1000;
e=w/100;
r=w%100;
t=r/10;
y=r%10;
for(u=1;u<=q;u++)
printf("M");
if(e>=5)
{printf("D");
for(u=1;u<=(e-5);u++)
printf("C");
}
if(e<5)
{
for(u=1;u<=e;u++)
printf("C");
}
if(t>=5)
{printf("L");
for(u=1;u<=(t-5);u++)
printf("X");
}
if(t<5)
{
for(u=1;u<=t;u++)
printf("X");
}
if(y>=5)
{printf("V");
for(u=1;u<=(y-5);u++)
printf("I");
}
if(y<5)
{
for(u=1;u<=y;u++)
printf("I");
}
return 0;



}

10/24/15, 4:14 PM
kanishk said...

#include

int main ()
{int year,q,w,e,r,t,y,u,i,o;
printf("enter ur num");
scanf("%d",&year);
q=year/1000;
w=year%1000;
e=w/100;
r=w%100;
t=r/10;
y=r%10;
for(u=1;u<=q;u++)
printf("M");
if(e>=5)
{printf("D");
for(u=1;u<=(e-5);u++)
printf("C");
}
if(e<5)
{
for(u=1;u<=e;u++)
printf("C");
}
if(t>=5)
{printf("L");
for(u=1;u<=(t-5);u++)
printf("X");
}
if(t<5)
{
for(u=1;u<=t;u++)
printf("X");
}
if(y>=5)
{printf("V");
for(u=1;u<=(y-5);u++)
printf("I");
}
if(y<5)
{
for(u=1;u<=y;u++)
printf("I");
}
return 0;



}

10/24/15, 4:16 PM
Unknown said...

you have to change the part:

predigits('L','D');
number = number - (500-100);

TO
predigits('C','D');
number = number - (500-100);

11/2/15, 1:41 AM
Unknown said...

right...

7/16/16, 12:18 PM
Anonymous said...

lol
check the numebr 499
the output will be ldxcix
which is the output for 549

12/1/16, 6:26 AM
Anonymous said...
This comment has been removed by the author.
12/1/16, 6:26 AM

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